培根密码加解密_二进制密码在线解密

全栈程序员-用户IM • 2022年10月25日上午8:36 • 未分类

大家好，又见面了，我是你们的朋友全栈君。如果您正在找激活码,请点击查看最新教程,关注关注公众号 “全栈程序员社区” 获取激活教程,可能之前旧版本教程已经失效.最新Idea2022.1教程亲测有效,一键激活。

Jetbrains全家桶1年46，售后保障稳定

0x00 介绍

培根密码实际上就是一种替换密码，根据所给表一一对应转换即可加密解密
它的特殊之处在于：可以通过不明显的特征来隐藏密码信息，比如大小写、正斜体等，只要两个不同的属性，密码即可隐藏

0x01 代码实现

脚本很简单，就是建立对应关系，对密文，或者明文进行相应的替换即可
需要注意的是输入的都应该是全小写字母或全大写字母，在脚本里也有说明
python脚本如下：

# coding:utf8

import re

alphabet = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']

first_cipher = ["aaaaa","aaaab","aaaba","aaabb","aabaa","aabab","aabba","aabbb","abaaa","abaab","ababa","ababb","abbaa","abbab","abbba","abbbb","baaaa","baaab","baaba","baabb","babaa","babab","babba","babbb","bbaaa","bbaab"]

second_cipher = ["aaaaa","aaaab","aaaba","aaabb","aabaa","aabab","aabba","aabbb","abaaa","abaaa","abaab","ababa","ababb","abbaa","abbab","abbba","abbbb","baaaa","baaab","baaba","baabb","baabb","babaa","babab","babba","babbb"]

def encode():
    upper_flag = False # 用于判断输入是否为大写
    string = raw_input("please input string to encode:\n")
    if string.isupper():
        upper_flag = True
        string = string.lower()
    e_string1 = ""
    e_string2 = ""
    for index in string:
        for i in range(0,26):
            if index == alphabet[i]:
                e_string1 += first_cipher[i]
                e_string2 += second_cipher[i]
                break
    if upper_flag:
        e_string1 = e_string1.upper()
        e_string2 = e_string2.upper()
    print "first encode method result is:\n"+e_string1
    print "second encode method result is:\n"+e_string2
    return


def decode():
    upper_flag = False  # 用于判断输入是否为大写
    e_string = raw_input("please input string to decode:\n")
    if e_string.isupper():
        upper_flag = True
        e_string = e_string.lower()
    e_array = re.findall(".{5}",e_string)
    d_string1 = ""
    d_string2 = ""
    for index in e_array:
        for i in range(0,26):
            if index == first_cipher[i]:
                d_string1 += alphabet[i]
            if index == second_cipher[i]:
                d_string2 += alphabet[i]
    if upper_flag:
        d_string1 = d_string1.upper()
        d_string2 = d_string2.upper()
    print "first decode method result is:\n"+d_string1
    print "second decode method result is:\n"+d_string2
    return


if __name__ == '__main__':
    print "\t\tcoding by qux"
    while True:
        print "\t*******Bacon Encode_Decode System*******"
        print "input should be only lowercase or uppercase,cipher just include a,b(or A,B)"
        print "1.encode\n2.decode\n3.exit"
        s_number = raw_input("please input number to choose\n")
        if s_number == "1":
            encode()
            raw_input()
        elif s_number == "2":
            decode()
            raw_input()
        elif s_number == "3":
            break
        else:
            continue