Mysql经典练习题50题「建议收藏」

大家好，又见面了，我是你们的朋友全栈君。如果您正在找激活码,请点击查看最新教程,关注关注公众号 “全栈程序员社区” 获取激活教程,可能之前旧版本教程已经失效.最新Idea2022.1教程亲测有效,一键激活。

Jetbrains全系列IDE使用 1年只要46元售后保障童叟无欺

网上关于这套练习题较多使用的是比较老的mysql版本，我使用的是 Server version: 8.0.15 MySQL

练习数据

数据表 –1.学生表 Student(SId,Sname,Sage,Ssex)

–SId 学生编号,Sname 学生姓名,Sage 出生年月,Ssex 学生性别

–2.课程表 Course(CId,Cname,TId) –CId –课程编号,Cname 课程名称,TId 教师编号

–3.教师表 Teacher(TId,Tname) –TId 教师编号,Tname 教师姓名

–4.成绩表 SC(SId,CId,score) –SId 学生编号,CId 课程编号,score 分数

创建测试数据

学生表 Student

create table Student(SId varchar(10),Sname varchar(10),Sage datetime,Ssex varchar(10));
insert into Student values('01' , '赵雷' , '1990-01-01' , '男');
insert into Student values('02' , '钱电' , '1990-12-21' , '男');
insert into Student values('03' , '孙风' , '1990-05-20' , '男');
insert into Student values('04' , '李云' , '1990-08-06' , '男');
insert into Student values('05' , '周梅' , '1991-12-01' , '女');
insert into Student values('06' , '吴兰' , '1992-03-01' , '女');
insert into Student values('07' , '郑竹' , '1989-07-01' , '女');
insert into Student values('09' , '张三' , '2017-12-20' , '女');
insert into Student values('10' , '李四' , '2017-12-25' , '女');
insert into Student values('11' , '李四' , '2017-12-30' , '女');
insert into Student values('12' , '赵六' , '2017-01-01' , '女');
insert into Student values('13' , '孙七' , '2018-01-01' , '女');

科目表 Course

create table Course(CId varchar(10),Cname nvarchar(10),TId varchar(10))
insert into Course values('01' , '语文' , '02');
insert into Course values('02' , '数学' , '01');
insert into Course values('03' , '英语' , '03');

教师表 Teacher

create table Teacher(TId varchar(10),Tname varchar(10))
insert into Teacher values('01' , '张三');
insert into Teacher values('02' , '李四');
insert into Teacher values('03' , '王五');

成绩表 SC

create table SC(SId varchar(10),CId varchar(10),score decimal(18,1))
insert into SC values('01' , '01' , 80);
insert into SC values('01' , '02' , 90);
insert into SC values('01' , '03' , 99);
insert into SC values('02' , '01' , 70);
insert into SC values('02' , '02' , 60);
insert into SC values('02' , '03' , 80);
insert into SC values('03' , '01' , 80);
insert into SC values('03' , '02' , 80);
insert into SC values('03' , '03' , 80);
insert into SC values('04' , '01' , 50);
insert into SC values('04' , '02' , 30);
insert into SC values('04' , '03' , 20);
insert into SC values('05' , '01' , 76);
insert into SC values('05' , '02' , 87);
insert into SC values('06' , '01' , 31);
insert into SC values('06' , '03' , 34);
insert into SC values('07' , '02' , 89);
insert into SC values('07' , '03' , 98);

练习题目

查询” 01 “课程比” 02 “课程成绩高的学生的信息及课程分数 1.1 查询同时存在” 01 “课程和” 02 “课程的情况 1.2 查询存在” 01 “课程但可能不存在” 02 “课程的情况(不存在时显示为 null ) 1.3 查询不存在” 01 “课程但存在” 02 “课程的情况
查询平均成绩大于等于 60 分的同学的学生编号和学生姓名和平均成绩
查询在 SC 表存在成绩的学生信息
查询所有同学的学生编号、学生姓名、选课总数、所有课程的总成绩(没成绩的显示为 null ) 4.1 查有成绩的学生信息
查询「李」姓老师的数量
查询学过「张三」老师授课的同学的信息
查询没有学全所有课程的同学的信息
查询至少有一门课与学号为” 01 “的同学所学相同的同学的信息
查询和” 01 “号的同学学习的课程完全相同的其他同学的信息
查询没学过”张三”老师讲授的任一门课程的学生姓名
查询两门及其以上不及格课程的同学的学号，姓名及其平均成绩
检索” 01 “课程分数小于 60，按分数降序排列的学生信息
按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩
查询各科成绩最高分、最低分和平均分：以如下形式显示：课程 ID，课程 name，最高分，最低分，平均分，及格率，中等率，优良率，优秀率及格为>=60，中等为：70-80，优良为：80-90，优秀为：>=90 要求输出课程号和选修人数，查询结果按人数降序排列，若人数相同，按课程号升序排列
按各科成绩进行排序，并显示排名， Score 重复时保留名次空缺 15.1 按各科成绩进行排序，并显示排名， Score 重复时合并名次
查询学生的总成绩，并进行排名，总分重复时保留名次空缺 16.1 查询学生的总成绩，并进行排名，总分重复时不保留名次空缺
统计各科成绩各分数段人数：课程编号，课程名称，[100-85]，[85-70]，[70-60]，[60-0] 及所占百分比
查询各科成绩前三名的记录
查询每门课程被选修的学生数
查询出只选修两门课程的学生学号和姓名
查询男生、女生人数
查询名字中含有「风」字的学生信息
查询同名同性学生名单，并统计同名人数
查询 1990 年出生的学生名单
查询每门课程的平均成绩，结果按平均成绩降序排列，平均成绩相同时，按课程编号升序排列
查询平均成绩大于等于 85 的所有学生的学号、姓名和平均成绩
查询课程名称为「数学」，且分数低于 60 的学生姓名和分数
查询所有学生的课程及分数情况（存在学生没成绩，没选课的情况）
查询任何一门课程成绩在 70 分以上的姓名、课程名称和分数
查询不及格的课程
查询课程编号为 01 且课程成绩在 80 分以上的学生的学号和姓名
求每门课程的学生人数
成绩不重复，查询选修「张三」老师所授课程的学生中，成绩最高的学生信息及其成绩
成绩有重复的情况下，查询选修「张三」老师所授课程的学生中，成绩最高的学生信息及其成绩
查询不同课程成绩相同的学生的学生编号、课程编号、学生成绩
查询每门功成绩最好的前两名
统计每门课程的学生选修人数（超过 5 人的课程才统计）。
检索至少选修两门课程的学生学号
查询选修了全部课程的学生信息
查询各学生的年龄，只按年份来算
按照出生日期来算，当前月日 < 出生年月的月日则，年龄减一
查询本周过生日的学生
查询下周过生日的学生
查询本月过生日的学生
查询下月过生日的学生

参考答案

--1. 查询" 01 "课程比" 02 "课程成绩高的学生的信息及课程分数
select * from
(select SC.SId, SC.score from SC where SC.CId = '01') as t1 inner join
(select SC.SId, SC.score from SC where SC.CId = '02') as t2 on t1.SId = t2.SId
where t1.score > t2.score
--1.1 查询同时存在" 01 "课程和" 02 "课程的情况
select * from
(select SC.SId, SC.score from SC where SC.CId = '01') as t1 inner join
(select SC.SId, SC.score from SC where SC.CId = '02') as t2 on t1.SId = t2.SId
--1.2 查询存在" 01 "课程但可能不存在" 02 "课程的情况(不存在时显示为 null )
select * from
(select SC.SId, SC.score from SC where SC.CId = '01') as t1 left join
(select SC.SId, SC.score from SC where SC.CId = '02') as t2 on t1.SId = t2.SId
-- 1.3 查询不存在" 01 "课程但存在" 02 "课程的情况
select * 
from sc
where SId not in (select SId from  sc where CId = '01') 
and CId = '02'
-- 2. 查询平均成绩大于等于 60 分的同学的学生编号和学生姓名和平均成绩
select t1.sid, t1.sname, t2.avgscore 
from student as t1 inner join (
select sc.sid, avg(sc.score) as avgscore from sc group by sc.sid 
having avgscore >= 60) as t2
on t1.sid = t2.sid
-- 3. 查询在 SC 表存在成绩的学生信息     注意⚠️DISTINCT⚠️关键字
select DISTINCT student.* 
from student, sc
where student.sid = sc.sid 
-- 4. 查询所有同学的学生编号、学生姓名、选课总数、所有课程的总成绩(没成绩的显示为null)
select student.sid, student.sname, t1.coursecount, t1.sumscore
from student inner join (
select sc.sid, count(sc.cid) as coursecount, sum(sc.score) as sumscore from sc group by sc.sid) as t1
on student.sid = t1.sid
-- 4.1 查有成绩的学生信息    注意⚠️EXISTS⚠️关键字
select student.* 
from student 
where student.sid in (
select DISTINCT sc.sid from sc)
select *
from student
where EXISTS(select * from sc where student.SId=sc.SId)
-- 5. 查询「李」姓老师的数量
select count(*) 
from teacher
where teacher.Tname like '李%'
-- 6. 查询学过「张三」老师授课的同学的信息
select student.* 
from student, sc 
where student.sid = sc.sid 
and sc.cid in (select cid from course, teacher where course.tid = teacher.tid and Tname = '张三')
-- 同时连接多张表
select student.*
from teacher  ,course  ,student, sc
where teacher.Tname='张三'
and   teacher.TId=course.TId
and   course.CId=sc.CId
and   sc.SId=student.SId
-- 7. 查询没有学全所有课程的同学的信息
-- 这种解法不包括什么课都没选的学生
select student.* from student, (select sid, count(cid) as coursecount from sc group by sid) as t1
where student.sid = t1.sid 
and t1.coursecount<>3
select student.*
from sc ,student
where sc.SId=student.SId
GROUP BY sc.SId
Having count(*)<(select count(*) from course)
-- 利用笛卡尔积可以把什么课都没选的同学查询出来
select DISTINCT student.*
from 
(select student.SId,course.CId
from student,course ) as t1 LEFT JOIN (SELECT sc.SId,sc.CId from sc)as t2 on t1.SId=t2.SId and t1.CId=t2.CId,student
where t2.SId is null
and   t1.SId=student.SId
select student.* from student
where student.sid not in (
select student.sid from sc, student 
where sc.sid = student.sid
group by sid 
having count(*) = (select count(*) from course))
-- 8. 查询至少有一门课与学号为" 01 "的同学所学相同的同学的信息
select DISTINCT student.* 
from sc, student
where sc.CId in (
select CId from sc where SId='01')
and sc.SId = student.SId
-- 9. 查询和" 01 "号的同学学习的课程完全相同的其他同学的信息
select DISTINCT student.*
from (
select student.SId, t.CId
from student ,(select sc.CId from sc where sc.SId='01') as t)
as t1 LEFT JOIN sc on t1.SId=sc.SId and t1.CId=sc.CId,student
where sc.SId is not null 
and t1.SId=student.SId
and t1.SId <>'01'
-- 10. 查询没学过"张三"老师讲授的任一门课程的学生姓名
-- solution1
select * 
from student 
where student.SId not in (
select student.SId from (
select student.SId, t.CId from (
select course.CId from course, teacher 
where  course.TId = teacher.TId and teacher.Tname = '张三') as t, student) as t1 
right join sc on t1.SId=sc.SId and t1.CId=sc.CId, student
where t1.SId=student.SId)
-- solution2
select *
from student 
where student.SId not in 
(
select student.SId
from student left join sc on student.SId=sc.SId 
where EXISTS 
(select *
from teacher ,course
where teacher.Tname='张三'
and   teacher.TId=course.TId
and 	course.CId=sc.CId))
-- 11.查询两门及其以上不及格课程的同学的学号，姓名及其平均成绩
select student.SId, student.Sname, t2.avgscore
from student, (select sc.SId, avg(sc.score) as avgscore from sc group by sc.SId) as t2
where student.SId = t2.SId
and student.SId in (
select t1.SId from
(select * from sc
where sc.score < 60) as t1
group by t1.SId
having count(*) >= 2)
-- 12. 检索" 01 "课程分数小于60，按分数降序排列的学生信息
select student.*, t1.score from student, (
select * from sc 
where sc.CId = '01' and sc.score < 60) as t1
where student.SId = t1.SId
order by t1.score DESC
-- 13. 按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩
select sc.*, t1.avgscore from sc left join
(select sc.SId, avg(sc.score) as avgscore 
from sc group by sc.SId) as t1
on sc.SId = t1.SId
order by t1.avgscore DESC
-- 14. 查询各科成绩最高分、最低分和平均分： 以如下形式显示：
-- 课程 ID，课程 name，最高分，最低分，平均分，及格率，中等率，优良率，优秀率 
-- 及格为>=60，中等为：70-80，优良为：80-90，优秀为：>=90 
-- 要求输出课程号和选修人数，查询结果按人数降序排列，若人数相同，按课程号升序排列
select sc.CId, max(sc.score) as '最高分', min(sc.score) as '最低分', avg(sc.score) as '平均分',
count(*) as '选修人数', sum(case when sc.score >= 60 then 1 else 0 end)/count(*) as '及格率',
sum(case when sc.score >= 70 and sc.score < 80 then 1 else 0 end)/count(*) as '中等率',
sum(case when sc.score >= 80 and sc.score < 90 then 1 else 0 end)/count(*) as '优良率',
sum(case when sc.score >= 90 then 1 else 0 end)/count(*) as '优秀率'
from sc 
group by sc.CId
order by count(*) DESC, sc.CId ASC
-- 15. 按各科成绩进行排序，并显示排名，Score 重复时保留名次空缺
SELECT *, RANK() OVER(PARTITION BY sc.cid ORDER BY sc.score DESC)排名
FROM sc;
-- 15.1 按各科成绩进行排序，并显示排名， Score 重复时合并名次
SELECT *, DENSE_RANK() OVER(PARTITION BY sc.cid ORDER BY sc.score DESC)排名
FROM sc;
-- 16. 查询学生的总成绩，并进行排名，总分重复时保留名次空缺
SELECT sc.SId, RANK() OVER(ORDER BY sum(sc.score) DESC)排名, sum(sc.score) as sumscore
FROM sc
GROUP BY sc.SId
ORDER BY sumscore DESC;
-- 16.1 查询学生的总成绩，并进行排名，总分重复时不保留名次空缺
SELECT sc.SId, DENSE_RANK() OVER(ORDER BY sum(sc.score) DESC)排名, sum(sc.score) as sumscore
FROM sc
GROUP BY sc.SId
ORDER BY sumscore DESC;
-- 17. 统计各科成绩各分数段人数：课程编号，课程名称，[100-85]，[85-70]，[70-60]，[60-0] 及所占百分比
select sc.CId, sum(case when sc.score >=85 then 1 else 0 end) as num_100_85,
sum(case when sc.score >=70 and sc.score <85 then 1 else 0 end) as num_85_70,
sum(case when sc.score >= 60 and sc.score < 70 then 1 else 0 end) as num_70_60,
sum(case when sc.score < 60 then 1 else 0 end) as num_60_0,
sum(case when sc.score >=85 then 1 else 0 end)/count(*) as p_100_85,
sum(case when sc.score >=70 and sc.score <85 then 1 else 0 end) /count(*) as p_85_70,
sum(case when sc.score >= 60 and sc.score < 70 then 1 else 0 end)/count(*) as p_70_60,
sum(case when sc.score < 60 then 1 else 0 end)/count(*) as p_60_0
from sc 
group by sc.CId
-- 18. 查询各科成绩前三名的记录
SELECT * 
FROM(
SELECT *, RANK() OVER (PARTITION BY sc.CId ORDER BY sc.score) as r
FROM sc) as A
WHERE A.r <= 3
-- 19. 查询每门课程被选修的学生数
SELECT sc.CId, COUNT(*)
FROM sc
GROUP BY(sc.CId)
-- 20. 查询出只选修两门课程的学生学号和姓名
SELECT DISTINCT student.SId, student.Sname 
FROM student, (
SELECT sc.SId, COUNT(*) as a
FROM sc
GROUP BY(sc.SId)) as A
WHERE student.SId = A.SId
AND A.a = 2
SELECT Distinct student.Sid, student.Sname
FROM student 
where student.SId in (
SELECT sc.SId 
FROM sc
GROUP BY sc.SId
having count(*)=2)
-- 21. 查询男生、女生人数
SELECT Ssex, count(*)
FROM student
GROUP BY student.Ssex
-- 22. 查询名字中含有「风」字的学生信息
SELECT *
FROM student
WHERE student.sname LIKE '%风%';
-- 23. 查询同名同姓学生名单，并统计同名人数
SELECT Sname, count(*)
FROM student
GROUP BY Sname
HAVING COUNT(*) >1;
-- 24. 查询 1990 年出生的学生名单
SELECT *
FROM student
WHERE sage LIKE '1990-%';
-- 25.查询每门课程的平均成绩，结果按平均成绩降序排列，平均成绩相同时，按课程编号升序排列
SELECT sc.CId, avg(sc.score) as avgscore
FROM sc
GROUP BY sc.CId
ORDER BY avg(sc.score) DESC, sc.CId
-- 26.查询平均成绩大于等于 85 的所有学生的学号、姓名和平均成绩
SELECT student.Sid, student.Sname, t.avgscore
FROM student, (
SELECT sc.SId, avg(sc.score) as avgscore
FROM sc
GROUP BY sc.SId) as t
WHERE student.SId = t.SId
AND t.avgscore >= 85
-- 27.查询课程名称为「数学」，且分数低于 60 的学生姓名和分数
SELECT student.Sname, t.score
FROM student, (
SELECT sc.SId, sc.score
FROM sc 
WHERE sc.score < 60
AND sc.CId = (SELECT CId FROM course WHERE course.Cname='数学')) as t
WHERE student.SId = t.SId
-- 28.查询所有学生的课程及分数情况（存在学生没成绩，没选课的情况）
SELECT st.*, sc.CId, sc.score
FROM student AS st
LEFT JOIN sc
ON st.SId = sc.SId
ORDER BY st.SId, sc.CId;
-- 29.查询任何一门课程成绩在 70 分以上的姓名、课程名称和分数
SELECT student.Sname, course.Cname, sc.score
FROM student, course, sc
WHERE student.SId = sc.SId
AND course.CId = sc.CId
AND sc.score > 70
ORDER BY sc.CId
-- 30.查询不及格的课程
SELECT sc.CId, sc.score
FROM sc
WHERE sc.score <60
ORDER BY sc.CId;
-- 31.查询课程编号为 01 且课程成绩在 80 分以上的学生的学号和姓名
SELECT student.SId, student.Sname 
FROM student, sc
WHERE student.SId = sc.SId
AND sc.CId = '01'
AND sc.score > 80
-- 32.求每门课程的学生人数
SELECT sc.CId, count(sc.SId)
FROM sc
GROUP BY sc.CId
-- 33.成绩不重复，查询选修「张三」老师所授课程的学生中，成绩最高的学生信息及其成绩
SELECT student.*, sc.score, sc.CId 
FROM student, sc
WHERE sc.CId = (SELECT course.CId 
FROM course, teacher
WHERE course.TId = teacher.TId
AND teacher.Tname = '张三')
AND student.SId = sc.SId
ORDER BY sc.score DESC
LIMIT 1
-- 34.成绩有重复的情况下，查询选修「张三」老师所授课程的学生中，成绩最高的学生信息及其成绩
SELECT * FROM(
SELECT student.*, sc.score, sc.CId, DENSE_RANK() OVER (ORDER BY sc.score DESC)排名 
FROM student, sc
WHERE sc.CId = (SELECT course.CId 
FROM course, teacher
WHERE course.TId = teacher.TId
AND teacher.Tname = '张三')
AND student.SId = sc.SId) as t
WHERE t.排名='1'
-- 35.查询不同课程成绩相同的学生的学生编号、课程编号、学生成绩
SELECT sc.SId, sc.CId, sc.score
FROM sc
WHERE sc.score in (
SELECT score FROM(
SELECT sc.score, count(sc.score) as count_people
FROM sc
GROUP BY sc.score) A
WHERE A.count_people > 1) 
SELECT s,c,score
FROM
(
SELECT max(score),avg(score),COUNT(score),student.s,c,score
FROM student
LEFT JOIN sc
ON student.s=sc.s
GROUP BY student.s
HAVING max(score)=avg(score) AND COUNT(score)>=2
) A;
-- 36.查询每门功成绩最好的前两名
SELECT * 
FROM (SELECT sc.SId, sc.CId, sc.score, row_number() over (PARTITION BY sc.CId ORDER BY sc.score DESC)排名
FROM sc
ORDER BY sc.score DESC) A
WHERE 排名 <= 2
ORDER BY A.CId, A.排名
-- 37.统计每门课程的学生选修人数（超过 5 人的课程才统计)
SELECT * 
FROM (
SELECT sc.CId, count(sc.SId) as count_people
FROM sc
GROUP BY sc.CId) A
WHERE A.count_people > 5
SELECT sc.CId,COUNT(sc.CId)
FROM sc
GROUP BY sc.CId
HAVING COUNT(sc.CId)>5 ;
-- 38.检索至少选修两门课程的学生学号
SELECT sc.SId, COUNT(sc.SId)
FROM sc
GROUP BY sc.SId
HAVING COUNT(sc.SId) >= 2 
-- 39.查询各学生的年龄，只按年份来算
SELECT SId, Sname, (year(curdate())-year(Sage)) as age 
FROM student
ORDER BY age
-- 40.按照出生日期来算，当前月日 < 出生年月的月日则，年龄减一
SELECT SId, Sname,timestampdiff(year,Sage,curdate())年龄
FROM student
ORDER BY 年龄;
-- 41. 查询本周过生日的学生
SET @day =8-dayofweek(curdate());
SELECT *
FROM student
WHERE date_format(Sage, '%m%d') 
BETWEEN date_format(curdate(),'%m%d') 
AND date_format (date_add(curdate(),interval @day day), '%m%d');
-- 42.查询下周过生日的学生
set @day =9-dayofweek(curdate());
SELECT *
FROM student
WHERE date_format(sage, '%m%d') 
BETWEEN date_format (date_add(curdate(),interval @day day), '%m%d')
AND date_format (date_add(curdate(),interval @day+6 day), '%m%d');
-- 43.查询本月过生日的学生
SELECT *
FROM student
WHERE date_format(Sage,'%m')=date_format(curdate(),'%m');
-- 44.查询下月过生日的学生
SELECT *
FROM student
WHERE date_format(Sage,'%m')=date_format(date_add(curdate(),interval 1 month),'%m');

发布者：全栈程序员-用户IM，转载请注明出处：https://javaforall.cn/192040.html原文链接：https://javaforall.cn

【正版授权，激活自己账号】： Jetbrains全家桶Ide使用，1年售后保障，每天仅需1毛

【官方授权正版激活】： 官方授权正版激活支持Jetbrains家族下所有IDE 使用个人JB账号...