JAVA 解析Xml字符串

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import java.io.StringReader;

import java.util.Iterator;


import java.util.List;


import org.dom4j.Document;


import org.dom4j.Element;


import org.dom4j.io.SAXReader;


import org.xml.sax.InputSource;


public class Test {

 public static void main(String[] args) throws Exception {

String Testxml="<?xml version=\"1.0\" encoding=\"utf-8\"?>\n" +
      "<CSubmitState xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\" xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns=\"http://tempuri.org/\">\n" +
      " <State>054</State>\n" +
      " <MgID>170479913</MgID>\n" +
      " <Msgtate>adadafa</Msgtate>\n" +
      " <Rserve>01</Rserve>\n" +
      "</CSubmitState>";

org.xml.sax.InputSource in = new org.xml.sax.InputSource(new StringReader(Testxml));
 in.setEncoding("UTF-8");
SAXReader reader = new SAXReader();
Document document = reader.read(in);
Element root = document.getRootElement();
List<Element> elements = root.elements();
for(Iterator<Element> it = elements.iterator();it.hasNext();){
   Element element = it.next();
   System.out.println(element.getName() + " : " + element.getTextTrim());
   if("Reserve".equals(element.getName())) {
      System.out.println(element.getName() + " : " + element.getTextTrim());
   }
}

 }

}

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