poj 1488 TEX Quotes 双引号的改写 （☆☆☆☆☆）

http://poj.org/problem?id=1488

曾经做过一个类似的，也是对双引号进行修改。

这题要使用整行读人，我习惯使用gets()函数，当然也有其他的函数get(cin,string s)、cin.getline(charArray, max_length,’\n’)。但有时做字符串题时会发生与换行符有关的错误，不能理解！

Sample Input

"To be or not to be," quoth the Bard, "that
is the question".
The programming contestant replied: "I must disagree.
To `C' or not to `C', that is The Question!"

Sample Output

``To be or not to be,'' quoth the Bard, ``that
is the question''.
The programming contestant replied: ``I must disagree.
To `C' or not to `C', that is The Question!''

Source Code

#include <stdio.h>
#include <string.h>


const int N = 1000;
int main(){
    
	int i,j,cnt=0;
	char src[N],dst[N];
	while(gets(src)){
    

		for(i=j=0;i<strlen(src);i++){
    
			if(src[i]!='"'){
    
				dst[j++]=src[i];
			}
			else {
    
				cnt=(cnt+1)%2;
				if(cnt){
    
					dst[j++]='`';
					dst[j++]='`';
				}
				else{
    
					dst[j++]='\'';
					dst[j++]='\'';				
				}
			}
		}
		dst[j]='
#include <stdio.h>
#include <string.h>
const int N = 1000;
int main(){

int i,j,cnt=0;
char src[N],dst[N];
while(gets(src)){

for(i=j=0;i<strlen(src);i++){

if(src[i]!='"'){

dst[j++]=src[i];
}
else {

cnt=(cnt+1)%2;
if(cnt){

dst[j++]='`';
dst[j++]='`';
}
else{

dst[j++]='\'';
dst[j++]='\'';				
}
}
}
dst[j]='\0';
printf("%s\n",dst);
}
return 0;
}';
		printf("%s\n",dst);
	}
	return 0;
}